Question 350394
{{{x^(1/8)y^(1/5)z^(1/3)=x^(15/120)y^(24/120)z^(40/120)=(x^15y^24z^40)^(1/120)=root(120,x^15y^24z^40)}}}



So {{{x^(1/8)y^(1/5)z^(1/3)^""=root(120,x^15y^24z^40)}}}



If you need more help, email me at <a href="mailto:jim_thompson5910@hotmail.com?Subject=Algebra%20Help">jim_thompson5910@hotmail.com</a>


Also, feel free to check out my <a href="http://www.freewebs.com/jimthompson5910/home.html">tutoring website</a>


Jim