Question 350304
Hi again,
As to odd integers, they differ by 2, let n,(n+2),(n+4)represent them
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the odd integers that the sum of the first and third is 33 more the second
n +(n + 4) = (n+2) +33
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Simplify and solve for n.
Then list n,(n+2), (n+4) as being the 3 odd consecutive integers

Hi 
Note: consecutive interger differ by 1.  Let x, 9x+1),x+2) represent the integers.
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Question states
n + (n+2) = (n+1) +33
n = 32
n = 
Intergers are 32,33 and 34
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check your answer
32 + 34 = 33 + 33
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twice the largerst is equal to the sum of thetwo smallest ones
Write as you Read and Solve
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2(n+2) = n + (n+1)