<PRE><B>Question 350283</B>
Kesha drove from Buffalo to Syracuse at an average rate of 48 miles per hour.
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B to S DATA:
rate = 48 mph ; time = x hrs ; distance = 48x miles
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 On the return trip along the same road she was able to travel at an average rate of 60 miles per hour. The trip from Buffalo to Syracuse took one-half hour longer than the return trip.
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S to B DATA:
rate = 60 mph ; time = x-(1/2) hrs ; distance = 60(x-(1/2)) = 60x-30 miles
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 How long did the return trip take?
Equation: 
distance = distance
48x = 60x-30
12x = 30
x = 5/2 hrs 
x-(1/2) = 5 hrs (time for return trip)
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Cheers,
Stan H.
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