Question 39599
Hi,

Let the two numbers be a, and b. Let a be the larger one. Then

a-b=1 so a=1+b

also ab=1, but a=1+b so (1+b)b=1

b^2+b-1=0

This is a quadratic equation, which we can solve by completing the square.

(b+1/2)^2-5/4=0

(b+1/2)^2=5/4

(Note b has to be posotive from question)

*[tex b+1/2=\sqrt{5}/2]

*[tex b=\frac{\sqrt{5}-1}{2}]

a=b+1 so *[tex a=\frac{\sqrt{5}+1}{2}]

Don't forget to go back and check the answer is right by working out ab.

Hope that helps,
Kev