Question 350174
Hi, 
*Note: put into the general slope-intercept format y = mx + b where m is the slope and b the y-intercept (the value of y where the line croasses the y-axis
.
-2x - y = 0
y = -2x
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Slope of the line is -(2/1) (change in y over change in x)
(line slopes to the left as the slope is a negative number
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y -intercept is 0.   Pt(0,0) a point on the line.
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Slope tells us Pt(1, -2) and Pt(-1, 2)are on the line.
{{{drawing(300,300, -10, 10, -10, 10,
circle(0, 0,0.2),
circle(1, -2,0.2),
circle(-1, 2,0.2),

graph( 300, 300, -10, 10, -10, 10, -2x))}}}