Question 350019
I think you mean bisect the area generated by the curve and the x-axis?
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{{{int((1/x^2),dx,1,a)=int((1/x^2),dx,a,8)}}}
{{{int((1/x^2),dx)=-1/x+C}}}
{{{-1/a+1=-1/8+1/a}}}
{{{-2/a=-9/8}}}
{{{1/a=9/16}}}
{{{a=16/9}}}
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{{{highlight(x=16/9)}}}