<PRE><B>Question 349979</B>
In a chemistry class, 12 L of a 12% alcohol solution must be mixed with a 20% solution to get a 14% solution. How many liters of the 20% solution are needed?
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Equation:
alcohol + alcohol = alcohol
0.12(12) + 0.20x = 0.14(12+x)
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Multiply thru by 100 to get:
12*12 + 20x = 14*12 + 14x
6x = 2*12
x = 4 liters (amt of 20% solution needed for the mixture)

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Cheers,
Stan H.
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