<PRE><B>Question 349765</B>
three divided by the difference of x and 7 minus 2 divided by x plus 7 equals
 3 times the reciprocal of the difference of x squared and 49
 what is x
:
Assume the problem is:
{{{3/((x-7))}}}-{{{2/((x+7))}}} = {{{3*(1/(x^2-49))}}}
:
x^2-49 is the difference of squares and can be factored
{{{3/((x-7))}}}-{{{2/((x+7))}}} = {{{3*(1/((x-7)(x+7))))}}}
:
Multiply by (x-7)(x+7), clears the denominators and you have:
3(x+7) - 2(x-7) = 3
:
3x + 21 - 2x + 14 = 3
:
3x - 2x + 35 = 3
:
x = 3 - 35
:
x = -32</PRE>