Question 39545
A) {{{x^3 < 8}}}
{{{-2 > x}}} and {{{x < 2}}}
Check:
<=====(-2)=====(2)----->
Plug in numbers to determine real solutions.
B) {{{x^3 - x^2 - 9x + 9 > 0}}}
{{{(x-1)(x+3)(x-3)>0}}}
<-----(-3)=====(1)-----(3)=====>
C) {{{(2x^2- 3x +1)/ (x+1) > 0}}}
{{{(2x^2 - 3x + 1) > 0}}}
{{{(2x-1)(x-1) > 0}}} Remember that {{{x}}} can not equal (-1).
<-----(-1)=====(1/2)-----(1)=====>