Question 349800
First, let's solve the given inequality



{{{y-8>2y-3}}} Start with the given inequality.



{{{y>2y-3+8}}} Add {{{8}}} to both sides.



{{{y-2y>-3+8}}} Subtract {{{2y}}} from both sides.



{{{-y>-3+8}}} Combine like terms on the left side.



{{{-y>5}}} Combine like terms on the right side.



{{{y<(5)/(-1)}}} Divide both sides by {{{-1}}} to isolate {{{y}}}. note: Remember, the inequality sign flips when we divide both sides by a negative number. 



{{{y<-5}}} Reduce.



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Answer:


So the answer is {{{y<-5}}} 



So ANY number that is less than -5 is a solution to the original inequality.



So for example, 6 is NOT a solution as it is NOT less than -5. However, -19 and -12 are both solutions since they are both less than -5.



Alternatively, you can plug in each possible solution into the given inequality and evaluate each side. If you get a true statement, then that given possible solution is actually a solution. If you get a false statement, then it's not a solution.



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Jim