Question 349711
Any positive odd number is of the form {{{2n+1}}} where {{{n>=0}}} (and n is an integer). So another positive odd number may look like {{{2m+1}}} where {{{m>=0}}} (and m is an integer). Also, we can make the condition that {{{m<>n}}}



Add the two numbers to get {{{(2n+1)+(2m+1)=(2m+2n)+(1+1)=2(m+n)+2=2(m+n+1)}}}



Notice how {{{2(m+n+1)}}} is of the form {{{2q}}} which is even where 'q' is some integer. Ie {{{q=m+n+1}}}



So {{{2(m+n+1)}}} is an even number which means that the sum of two positive odd numbers is ALWAYS a positive even number.




Example: 3 and 5 are positive odd numbers and 3+5 = 8 is an even number.



If you need more help, email me at <a href="mailto:jim_thompson5910@hotmail.com?Subject=Algebra%20Help">jim_thompson5910@hotmail.com</a>


Also, feel free to check out my <a href="http://www.freewebs.com/jimthompson5910/home.html">tutoring website</a>


Jim