Question 349677
{{{ y-1=x-2}}}
{{{1 = x - y}}}
{{{y+5=x+4}}}
{{{1 = x - y}}}
SO the equations are the same line.

Put it in slope intecept
{{{1 = x - y}}}
{{{y = x - 1}}} is in the form (y = mx + b) when m=1 and b = -1

To find the line perpendicular, it needs a slope that is the negative reciprocal of the given line.
{{{y = -x - 1}}}
There are an infinite number of lines perpendicalar to the given line (all you need to do so show that is leave the slope as is and chang ethe value of b (in this case -1) to any number.

{{{graph(400,400, -10,10,-10,10, x-1, -x-1)}}}