Question 349662
You can do this with logs:
{{{1300*1.0925^35}}}
Take the log. Note that the log of a product
is the sum of the logs of the factors
{{{log(1300) + 35*log(1.0925)}}}
{{{log(13*100) + 35*log(1.0925)}}}
{{{log(13) + log(100) + 35*log(1.0925)}}}
{{{1.1139 + 2 + 35*.0384}}}
{{{3.1139 + 1.3448}}}
{{{4.4587}}}
This is the log of the answer.
Now you have to find {{{10^4.4587}}}
which is the antilog
{{{10^4.4587 = 28754.1}}}