Question 349637
{{{cot(x/2) = sqrt(3)/3}}}
If you know your special angles well, then you know that the reference angle for this is {{{pi/6}}}. And since cot is positive in the first and third quadrants:
{{{x/2 = pi/6 + 2*pi*n}}} (where n i s any integer)
or
{{{x/2 = pi + pi/6 + 2*pi*n = (7*pi)/6 + 2*pi*n}}} (where n i s any integer)
To solve for x we just multiply each side of each equation by 2:
{{{x = pi/3 + 4*pi*n}}} (where n i s any integer)
or
{{{x = (7*pi)/3 + 4*pi*n}}} (where n i s any integer)