Question 349501
First find the slope using the two points.
{{{m=(y[2]-y[1])/(x[2]-x[1])=(0-(-3))/(-1-2)=3/-3=-1}}}
Perpendicular lines have slopes that are negative reciprocals,
{{{m[1]*m[2]=-1}}}
{{{-1*m[2]=-1}}}
{{{m[2]=1}}}
Use the slope-intercept form of a line, {{{y=mx+b}}}
{{{y=x+b}}}
Use the origin ({{{0}}},{{{0}}}) to solve for {{{b}}}.
{{{0=-0+b}}}
{{{b=0}}}
{{{highlight(y=x)}}}
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{{{drawing(300,300,-5,5,-5,5,grid(1),circle(2,-3,0.15),circle(-1,0,0.15),line(2,-3,-1,0),graph(300,300,-5,5,-5,5,x))}}}