Question 349563
The radius bisects the chord. The chords are of length 8 & 6.
The radius,perpendicular distance from center to chord and the chord form a right triangle.
Apply pythagorean formula
for both triangles

Radius  is the hypotenuse.
5^2-4^2
25-16=9
sqrt9 = 3
....
5^2-3^2
25-9=16
sqrt16=4
the distance between the chords = 1 in.