Question 349504
{{{64x^2-16}}} Start with the given expression.



{{{(8x)^2-16}}} Rewrite {{{64x^2}}} as {{{(8x)^2}}}.



{{{(8x)^2-(4)^2}}} Rewrite {{{16}}} as {{{(4)^2}}}.



Notice how we have a difference of squares {{{A^2-B^2}}} where in this case {{{A=8x}}} and {{{B=4}}}.



So let's use the difference of squares formula {{{A^2-B^2=(A+B)(A-B)}}} to factor the expression:



{{{A^2-B^2=(A+B)(A-B)}}} Start with the difference of squares formula.



{{{(8x)^2-(4)^2=(8x+4)(8x-4)}}} Plug in {{{A=8x}}} and {{{B=4}}}.



So this shows us that {{{64x^2-16}}} factors to {{{(8x+4)(8x-4)}}}.



In other words {{{64x^2-16=(8x+4)(8x-4)}}}.



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