Question 349248
{{{y=(x-7)^3}}}
Interchange {{{x}}} and {{{y}}} and solve for {{{y}}}. 
The new {{{y}}} is the inverse of the original {{{y}}}. 
{{{highlight(x)=(highlight(y)-7)^3}}}
{{{root(3,x)=y-7}}}
{{{yinv=root(3,x)+7}}}
{{{f^(-1)(x)=root(3,x)+7}}}