Question 4917
(x+a)(x+b) --> {{{x^2 + (a+b)x + ab}}} and you have 1x ie (a+b) has to be equal to +1


So, pick any pair of numbers that add to 1 eg +4 and -3...your c value here is -12: {{{x^2 + x -12}}} --> (x+4)(x-3) etc.


jon.