Question 349148
1.{{{y=x+8 }}}
2.{{{ x+y=2}}}
Use substitution,  substitute eq. 1 into eq. 2 and solve for {{{x}}}.
{{{x+(x+8)=2}}}
{{{2x+8=2}}}
{{{2x=-6}}}
{{{highlight(x=-3)}}}
Now use eq. 1 to solve for y.
{{{y=-3+8}}}
{{{highlight(y=5)}}}
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Verify by plugging the solutions into the original equations.
{{{y=x+8}}}
{{{5=-3+8}}}
{{{5=5}}}
True.
{{{x+y=2}}}
{{{-3+5=2}}}
{{{2=2}}}
True.
It's a good solution.