Question 349050
{{{(4c)/(6c)=(2*2*c)/(2*3*c)=(cross(2)*2*cross(c))/(cross(2)*3*cross(c))=2/3}}}
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{{{(3x-12)/(16-4x)= (3(x-4))/(-4(x-4))= (3*cross((x-4)))/(-4*cross((x-4)))=-(3/4)}}}

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{{{( 5x-15)/(9-3x)= (5(x-3))/(-3(x-3))=(5*cross((x-3)))/(-3*cross((x-3)))= -(5/3)}}}