Question 348991
{{{((x+5)(x-3))/((x+2))}}} * {{{1/((x+5)(x+2))}}}
It's a lot easier if you can cancel, here you can cancel (x+5), then you have:
{{{((x-3))/((x+2))}}} * {{{1/((x+2))}}} = {{{((x-3))/((x^2 + 4x + 4))}}}