Question 39513
y(x) = Ax^2 + Bx + C
y(0) will be the y-intercept. There should be just one.
This is found by setting x = 0 in the equation, so
y(0) = A(0) + B(0) + C
y(0) = C
The x-intercept(s) is found by setting y(x) = 0
There may be 0, 1, or 2 x-intercepts
Ax^2 + Bx + C = 0 solve for x
The formula is
 {{{x = (-B +- sqrt( B^2-4*A*C ))/(2*A) }}}