Question 349073
If the length and width of rectangle A are 10 percent less and 30 percent less,
 respectively, than the length and width of rectangle B, the area of A is equal
 to what percent of the area of B?
:
Let L = length of rectangle B
Let W = width of B
then
.9L = Length of rectangle A
.7W = width of A
:
{{{(.9L*.7W)/(L*W)}}} = {{{(.63LW)/(LW)}}} 
Cancel LW
{{{.63/1}}} * 100 = 63%