Question 349042
I found a way to get that answer. I'm not
positive it's right.
B = black
R = red
The cards drawn can be
BB
BR
RB
RR
The different ways to get BB or RR are
{{{(26/52)*(25/52)}}}
The different ways to get BR or RB are
{{{(26/52)*(26/52)}}}
My fraction should be BB / (BB + BR + RB + RR) =
{{{((26*25)/52^2) / (2*((26*25)/52^2 + 26^2/52^2))}}} = 
{{{(26*25) / (2*(26*25 + 26*26))}}} =
{{{25/(2*(25 + 26))}}} = 
{{{25 / (2*51)}}}
{{{25/102}}}