Question 349000


{{{(2x-1)^2+5=14}}} Start with the given equation.



{{{(2x-1)^2=14-5}}}Subtract {{{5}}} from both sides.



{{{(2x-1)^2=9}}} Combine like terms.



{{{2x-1=""+-sqrt(9)}}} Take the square root of both sides.



{{{2x-1=sqrt(9)}}} or {{{2x-1=-sqrt(9)}}} Break up the "plus/minus" to form two equations.



{{{2x-1=3}}} or {{{2x-1=-3}}}  Take the square root of {{{9}}} to get {{{3}}}.



{{{2x=1+3}}} or {{{2x=1-3}}} Add {{{1}}} to both sides.



{{{2x=4}}} or {{{2x=-2}}} Combine like terms.



{{{x=2}}} or {{{x=-1}}} Divide both sides by {{{2}}} to isolate {{{x}}}.



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Answer:



So the solutions are {{{x=2}}} or {{{x=-1}}}.



You can also represent the solutions as the solution set {2, -1}



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