Question 349003
2/x^2-4 subtracted by 1/x^2-3x+2
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 1/x^2-3x+2 - 2/x^2-4

x^2-4 - 2(x^2-3x+2) / (x^2-4)(x^2-3x+2)
x^2-4 -2x^2+6x-4 /(x^2-4)(x^2-3x+2)
-x^2+6x-8 /(x^2-4)(x^2-3x+2)
-(x^2-6x+8)/(x^2-4)(x^2-3x+2)
-(x-4)(x-2) /(x^2-4)(x-2)(x-1)
-(x-4)/(x^2-4)(x-1)