Question 348768
X/2+(X+2)/5=48
[5X+2(X+2)]/2*5=48
[5X+2X+4]/10=48
[7X+4]/10=48
7X+4=10*48
7X+4=480
7X=480-4
7X=476
X=476/7
X=68 ANSWER FIR TGHE FIRST INTEGER.
68+2=70 ANS. FOR THE SECOND INTEGER.
PROOF:
68/2+70/5=48
34+14=48
48=48