Question 348777
from the looks of this your simply plugging in x and solving for y
{{{8x-4y=-12}}}; x=-3,-1,1
{{{8(-3)-4y=-12}}}; x=-3
{{{(-24)-4y=-12}}};  Add 24
{{{-4y=12}}}; divide by -4
{{{y=-3}}}; x=-3
<p>
{{{8(-1)-4y=-12}}}; x=-1
{{{(-8)-4y=-12}}}; add 8
{{{-4y=-4}}}; divide by -4
{{{y=1}}}; x=-1
<p>
{{{8(1)-4y=-12}}}; x=1
{{{8-4y=-12}}}; subtract 8
{{{-4y=-20}}}; divide by -4
{{{y=5}}}; x=1