Question 348627
Let the 4 integers be {{{N}}}, {{{N+2}}}, {{{N+4}}}, and {{{N+6}}}.

{{{-2(N+N+6)=-(N+4)-20}}}
{{{-2(2N+6)=-N-4-20}}}
{{{4N+12=N+24}}}
{{{3N=12}}}
{{{highlight(N=4)}}}
The integers are 4,6,8, and 10.