<PRE><B>Question 348669</B>
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Let *[tex \Large x] represent the shortest side. Then the longest side must be *[tex \Large x\ +\ 4], and the other side must be *[tex \Large \frac{x\ +\ x\ 4}{2}\ =\ x\ +\ 2].  And finally:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ x\ +\ 2\ +\ x\ +\ 4\ =\ 24]


Solve for *[tex \Large x], then calculate *[tex \Large x\ +\ 2] and *[tex \Large x\ +\ 4]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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