Question 348633
a) There are {{{2^5}}} or {{{32}}} possible combinations of boys and girls.
1 combination has 5 boys, 0 girls
5 combination has 4 boys, 1 girls
10 combination has 3 boys, 2 girls
10 combination has 2 boys, 3 girls
5 combination has 1 boys, 4 girls
1 combination has 0 boys, 5 girls
P(2 boys)={{{10/32=5/16}}}
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b) If the first born is male, then there are 16 possible combinations.
1 combination has 4 boys, 0 girls
4 combination has 3 boys, 1 girls
6 combination has 2 boys, 2 girls
4 combination has 1 boys, 3 girls
1 combination has 0 boys, 4 girls
P(2 girls, given first born male)={{{6/16=3/8}}}
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c)P(last male)={{{1/2}}}, independent of any previous births.