Question 348621
Let F be the number of $5, T the number of $10, and Y the number of $20 bills.
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"A wallet contains $460 in $5, $10, and $20 bills."
1.{{{5F+10T+20Y=460}}}
"The number of $5 bills exceeds twice the number of $10 bills by 4"
2.{{{F=2T+4}}}
"the number of $20 bills is 6 fewer than the number of $10 bills."
3.{{{Y=T-6}}}
Substitute eq. 2 and 3 into eq. 1,
{{{5(2T+4)+10T+20(T-6)=460}}}
{{{10T+20+10T+20T-120=460}}}
{{{40T-100=460}}}
{{{40T=560}}}
{{{T=14}}}
Then from eq. 2,
{{{F=28+4}}}
{{{F=32}}}
Then from eq. 3,
{{{Y=14-6}}}
{{{Y=8}}}
You have 8 $20 bills, 14 $10 bills, and 32 $5 bills.