Question 347981
The answer is actually {{{x>1}}}



First, break {{{-2 (3 + x) < 4x + 4 < 8x}}} into {{{-2(3+x)<4x+4}}} and {{{4x+4<8x}}}.


Next solve each inequality separately to get {{{x>-5/3}}} and {{{x>1}}}



You can combine these answers to get {{{x>1}}}



So the solution to {{{-2 (3 + x) < 4x + 4 < 8x}}} is {{{x>1}}}. This answer has been verified.