Question 348248
Hi,
*Note: first isolate of the square roots to one side of the equation:
{{{sqrt(y-2)+3 = sqrt(5y+1)}}}
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To solve:  SQUARE BOTH SIDES OF THE EQUATION
{{{ (y-2)+ 6*sqrt(y-2)+9 = (5y+1)}}}
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combine like terms:
{{{6*sqrt(y-2)= 4y-6}}}
{{{3*sqrt(y-2)= 2y-3}}}
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SQUARE BOTH SIDE OF THIS EQUATION
{{{9*(y-2)= 4y^2 -12y +9}}}
{{{0= 4y^2 -21y +27}}}
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Solve with the Quadratic Formula:
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
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*[invoke quadratic "x", 4, -21, 27]