Question 348296
Hi,
*Note: Question poses the time being the same for both train, one traveling at speed x , the slower at speed (x-10)
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t= (d/r)
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{{{(210/(x-10))= (260/x)}}}
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Solve by cross multiplying
{{{210*x=260*(x-10)}}}
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Simplify and solve for x
{{{210*x=260*(x-10)}}}
{{{210*x=260*x-260*10)}}}
{{{2600=50x}}}
{{{x=52mph}}}  
The other 42mph  (x-10)
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Check your answer
260mi/52mph = 5hr
210mi/42mph = 5hr