Question 348289
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*[tex \LARGE\ \ \ \ \ \ \ \ \ \ x\ =\ 10cos\theta]


so


*[tex \LARGE\ \ \ \ \ \ \ \ \ \ x^2\ =\ 100cos^2\theta]


so


*[tex \LARGE\ \ \ \ \ \ \ \ \ \ \sqrt{100\ -\ 100cos^2\theta}]


*[tex \LARGE\ \ \ \ \ \ \ \ \ \ \sqrt{100\left(1\ -\ cos^2\theta\right)}]


*[tex \LARGE\ \ \ \ \ \ \ \ \ \ \sqrt{100\left(sin^2\theta\right)}]


*[tex \LARGE\ \ \ \ \ \ \ \ \ \ 10sin\theta]


which is valid for the first quadrant, i.e. *[tex \LARGE 0\ <\ x\ <\ \frac{\pi}{2}]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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