<PRE><B>Question 348179</B>
Solve x^2+3x-10=0 
x^2+3x=10 
Next step is to multiply each term by four times the original coefficient of the x^2 term 
4x^2+12x=40 
Next square the original coefficient of x and add it to both sides of the equation: 
4x^2+12x+9=40+9 
4x^2+12x+9=49 
Next is to take the square root of both sides
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The left side factors as (2x+3)^2
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(2x+3)^2 = 49
Taking the square root of both sides you get:
2x+3 = 7 or 2x+3 = -7
2x = 4 or 2x = -10
x = 2 or x = -5
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Cheers,
Stan H.
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