Question 348136
Problem 1: (√x+4) +2 = (√(x + 20))
I know the answer is 5, but do not understand how to work the problem.
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Square both sides to get:
(x+4) + 4(sqrt(x+4)) + 4 = x + 20
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4sqrt(x+4) = 12
sqrt(x+4) = 3
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Square both sides to get:
x+4 = 9
x = 5
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Problem 2: (5√x-2) -3 = (√19x-29)
Square both sides to get:
25(x-2) - 6*5sqrt(x-2) + 9 = 19x-29
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25x-50 - 30sqrt(x-2) = 19x-38
-30sqrt(x-2) = 12-6x
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(5√x-2) -3 = (√19x-29)
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x cannot be 2
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Final Answer: x = 27
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Cheers,
Stan H.
-5sqrt(x-2) = 2-x
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Square both sides:
25(x-2) = 4 - 4x + x^2
25x-50 = 4 - 4x + x^2
x^2 -29x+54 = 0
(x-27)(x-2) = 0
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x = 27 or x = 2
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Checking in original equation:




How do you get 27 as the answer?