Question 348135

xyz=4 and y^2z=5

So, we can solve for z from the second equation:

z = 5/y^2

and we can plug this into the first one:

xy(5/y^2)=4

Cross out the y:

x5/y = 4

5x = 4y

x = 4y/5

divide by y:

x/y = 4/5