Question 348013


1st number = x
2nd number = y

2(x+y)=xy

x=6y

plug in the x into the above equation:

2(6y+y)=6y(y)
12y+2y = 6(y^2)
14y=6(y^2)
divide both sides by y:

14=6y

so, y = 14/6 which is 7/3.

Now, we can find x:

x = 6(7/3) which is 42/3 which is 14. 

So, the two positive numbers are 7/3 and 14.