<PRE><B>Question 348012</B>


sqrt(x+4) + 8 = o

bring the 8 to the other side:

sqrt(x+4) = -8

square both sides to get rid of the square root:

(x+4) = 64

bring the 4 to the other side:

x = 60

The thing is when you plug in the 60 into the equation, and you take the square root of 64, it can be + or - 8. if it is negative, then the equation works, and if it is positive, then the answer is not 0, it is 16:

sqrt(64) + 8 =0

8 + 8 = 16 which does not equal 0, so

we have a restriction to this problem: sqrt(64) cannot be positive.

 we get -8 + 8 = 0. </PRE>