Question 348012
~((x+4))+8=0

Since 8 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 8 from both sides.
~((x+4))=-8

To remove the radical on the left-hand side of the equation, square both sides of the equation.
(~((x+4)))^(2)=(-8)^(2)

Simplify the left-hand side of the equation.
(x+4)=(-8)^(2)

Squaring an expression is the same as multiplying the expression by itself 2 times.
(x+4)=((-8)(-8))

Multiply -8 by -8 to get 64.
(x+4)=((64))

Remove the parentheses around the expression 64.
(x+4)=(64)

Remove the parentheses around the expression 64.
(x+4)=64

Remove the parentheses around the expression x+4.
x+4=64

Since 4 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 4 from both sides.
x=-4+64

Add 64 to -4 to get 60.
x=60

Verify each of the first set of solutions by substituting them into the original equation and solving.  In this case, none of the solutions are valid.
No Solution