Question 39438
(10y^2 + 15y) / (35y^2 - 5y)
we can factor both and get
(10y^2 + 15y) / (35y^2 - 5y) =
5y(2y + 3) / 5y(7y - 1)
now notice the 5y's cancel, leaving us
(2y + 3) / (7y - 1)