Question 347987
Hi
*Note: will express both terms with common denomiator {{{(18y^2))}}}

{{{((8)/(9y))-((5)/(18y^2))}}}
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Multiply both numerator and denominator of first term  by 2*y
{{{(16y/18y^2)-((5)/(18y^2))}}}
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Express with the common denominator
{{{(16y-5)/(18y^2))}}}