Question 347866
So the bin has {{{65}}} good, {{{12}}} bad, {{{77}}} total.
P(1st good)={{{65/77}}}
P(2nd good)={{{65/77}}}
P(3rd good)={{{65/77}}}
P(4th good)={{{65/77}}}
P(5th good)={{{65/77}}}
P(all good)={{{(65/77)(65/77)(65/77)(65/77)(65/77)}}}
P(all good)={{{0.4287}}}
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{{{P=0.844}}} is the probability of picking the first good one out.
But you're doing it 5 times, so you need to multiply that value 5 times.