Question 347708
Let x & x-10 be the 2 sides.
x^2+(x-10)^2=22^2
x^2+x^2-20x+100=484
2x^2-20x+100-484=0
2x^2-20x-384=0
2(x^2-10x-192)=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
x=(10+-SQRT[-10^2-4*1*-192])/2*1
x=(10+-sqrt[100+768])/2
x=(10+-sqrt868)/2
x=(10+-29.46)/2
x=39.46/2
x=19.73 ans.
x=(10-29.46)/2
x=-19.46/2
x=-9.73 ans.