Question 347721
3[(2-3)^2 + (6 - 4)^2] ... Start with the given expression.



3[(-1)^2 + (2)^2] ... Subtract.



3[1 + 4] ... Square each term.



3[5] ... Add



15 ... Multiply



So 3[(2-3)^2 + (6 - 4)^2] = 15



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