Question 347699
Your reply suggests: the real task at hand, is in fact: "In each case, find all the real number solutions (if any) for the given equation." 
where "in each case" evidently refers to a number of given equations: 
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Would recommend visitng the idea that "0" in the denominator is not allowed:  therefore the real number solutions for this particular equation would be:
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All real numbers with the exception of t=2

Hi,
*Note: Substitute the value of t given for t.
h(t)=(5t-4)/(t-2)
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h(15)=(75-4)/(15-2)
h(15)= 71/13
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h(0) = -4/-2
h(0) = 2