Question 347473
2 10/13 = 36/13

C takes n days to do one job.
B takes (3/4) n days to do one job.
A takes (2/3) [(3/4) n] days to do one job. [= n/2 days to do one job.]

C can complete 1/n jobs in a day.
B can complete 4/(3n) jobs in a day.
A can complete 2/n jobs in a day.

36/13 days * [1/n jobs/day + 4/(3n) jobs/day + 2/n jobs/day] = 1 job.

solve for n, then plug-n-chug into:

C takes n days to do one job.
B takes (3/4) n days to do one job.
A takes n/2 days to do one job.